Kai Chew's answer to Help's Secondary 3 E Maths Singapore question.
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(x-(-3))(x-5) = 0
(x+3)(x-5) = 0
x^2 + 3x - 5x - 15 = 0
x^2 - 2x - 15 = 0
By comparing coefficients,
b = -2, c = -15
(x+3)(x-5) = 0
x^2 + 3x - 5x - 15 = 0
x^2 - 2x - 15 = 0
By comparing coefficients,
b = -2, c = -15
Date Posted:
1 year ago
I need the working for part b
i added it alr
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