Kai Chew's answer to Macdaddy's Secondary 3 E Maths Singapore question.
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b) y = x^2 +2x - 3
Let a be x coordinate of Q.
y = (x+3)(x-a)
y = x^2 + 3x - ax - 3a
By comparing coefficients,
3-a = 2
or -3 = -3a
THEREFORE,
a=1
Q(1,0)
Let a be x coordinate of Q.
y = (x+3)(x-a)
y = x^2 + 3x - ax - 3a
By comparing coefficients,
3-a = 2
or -3 = -3a
THEREFORE,
a=1
Q(1,0)
Date Posted:
1 year ago
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