Kai Chew's answer to riz's Secondary 3 A Maths Singapore question.
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(x+1)^2 is always more than or equal to 0.
Try subbing in any value of x, ull get 0 or higher.
Thus, 5(x+1)^2 is always more than or equal to zero.
Hence, 5(x+1)^2 + 6 is always 6 or higher
Try subbing in any value of x, ull get 0 or higher.
Thus, 5(x+1)^2 is always more than or equal to zero.
Hence, 5(x+1)^2 + 6 is always 6 or higher
Date Posted:
1 year ago
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