Eric Nicholas K's answer to LockB's Junior College 1 H2 Maths Singapore question.
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The explanation part
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Date Posted:
1 year ago
sorry for late reply! did receive any notifications for it....
i still dont understand the "in other words, for n=-1 part thoo..."
i still dont understand the "in other words, for n=-1 part thoo..."
a times b^n
If n = -1, it becomes a/b.
f'(x) times [f(x) ]^n
If n = -1, it becomes f'(x) times [f(x)]^-1 which will become f'(x) / f(x). I was just rewriting the format to let you see the format of writing. Usually such integrals (with power "-1") are written in fractional format instead.
If n = -1, it becomes a/b.
f'(x) times [f(x) ]^n
If n = -1, it becomes f'(x) times [f(x)]^-1 which will become f'(x) / f(x). I was just rewriting the format to let you see the format of writing. Usually such integrals (with power "-1") are written in fractional format instead.
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