C's answer to Fuzzy's Primary 6 Maths Measurement Singapore question.
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13 easy
2 medium
1 difficult
Maximum = 16 questions
2 medium
1 difficult
Maximum = 16 questions
Date Posted:
2 years ago
Can you please provide equation
This question is more of guess and check, below is my explanation, hope it helps.
If Anita answers AT LEAST one of each question, the minimum point is 2+5+7 = 14
43-14=29
To have maximum questions, divide 29 by 2 to get a larger quotient(14) and smaller remainder (1).
But, since there is no question with 1 point, have to make remainder 5 as it is the next possible point.
To do that, the quotient * divisor must equal 4, so minus 2 from 14 which gives 12 (“new” quotient) and remainder 5.
The remainder 5 represent 1 medium question (5points)
Easy = 12 + 1(minimum) = 13
Medium = 1 + 1(minimum) = 2
Difficult = 1(minimum) = 1
If Anita answers AT LEAST one of each question, the minimum point is 2+5+7 = 14
43-14=29
To have maximum questions, divide 29 by 2 to get a larger quotient(14) and smaller remainder (1).
But, since there is no question with 1 point, have to make remainder 5 as it is the next possible point.
To do that, the quotient * divisor must equal 4, so minus 2 from 14 which gives 12 (“new” quotient) and remainder 5.
The remainder 5 represent 1 medium question (5points)
Easy = 12 + 1(minimum) = 13
Medium = 1 + 1(minimum) = 2
Difficult = 1(minimum) = 1
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