Ng Peng Liang's answer to Jessica's Secondary 3 E Maths Singapore question.
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(i)
Angle FED = Angle BEA
Angle DFE = Angle ABE (Corresponding angle)
Hence, triangle FED is similar to triangle BEA with all the same angles
(iii)
Triangle DEA is similar to triangle BFC, hence they are proportionate.
2ED = 3CB
2DF = 3CF
DF + CF = 10cm
DF = 10cm - CF
Sub DF
2(10cm - CF) = 3CF
10cm - CF = 1.5CF
2.5CF = 10cm
CF = 4cm
Hope it helps :)
Angle FED = Angle BEA
Angle DFE = Angle ABE (Corresponding angle)
Hence, triangle FED is similar to triangle BEA with all the same angles
(iii)
Triangle DEA is similar to triangle BFC, hence they are proportionate.
2ED = 3CB
2DF = 3CF
DF + CF = 10cm
DF = 10cm - CF
Sub DF
2(10cm - CF) = 3CF
10cm - CF = 1.5CF
2.5CF = 10cm
CF = 4cm
Hope it helps :)
Date Posted:
1 year ago
Thank youuu!!
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