CY Lew's answer to Sandy's Primary 6 Maths Speed Singapore question.
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a) At the 1st meeting, using speed triangle,
90xT + 110xT = 400
T = 2 min
Distance covered by Allen = 90x2=180 m
b) Time for each lap,
Aileen = 400 ÷ 90 = 40/9 min
Betty = 400 ÷ 110 = 40/11 min
Using HCF n LCM,
Next meeting occurs at the end of,
Betty's 11th lap n Aileen's 9 lap
Thus,
Time = 40 min later
90xT + 110xT = 400
T = 2 min
Distance covered by Allen = 90x2=180 m
b) Time for each lap,
Aileen = 400 ÷ 90 = 40/9 min
Betty = 400 ÷ 110 = 40/11 min
Using HCF n LCM,
Next meeting occurs at the end of,
Betty's 11th lap n Aileen's 9 lap
Thus,
Time = 40 min later
Date Posted:
2 years ago
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