Mimosa's answer to jq's Secondary 3 E Maths Singapore question.
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Date Posted:
2 years ago
I don't think length AB is 8cm.
From the right-angled triangle, PQ is 8cm (sum of both radius).
Hence, (AB)^2 + (2)^2 = (8)^2. AB = sqrt 60. To find θ, use cos(θ) = 2/8 instead.
From the right-angled triangle, PQ is 8cm (sum of both radius).
Hence, (AB)^2 + (2)^2 = (8)^2. AB = sqrt 60. To find θ, use cos(θ) = 2/8 instead.
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