Ian Tan's answer to kristen's Secondary 4 A Maths Singapore question.
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Consider a quadratic equation ax^2+bx+c=0 with roots p and q
Using sum of roots and product of roots,
a=1
b=-(k+1)
c=1
For p and q to be real and distinct,
b^2-4ac > 0
Hence [-(k+1)]^2 - 4 > 0
Solving for k gives k > 1 or k < -3
Using sum of roots and product of roots,
a=1
b=-(k+1)
c=1
For p and q to be real and distinct,
b^2-4ac > 0
Hence [-(k+1)]^2 - 4 > 0
Solving for k gives k > 1 or k < -3
Date Posted:
1 year ago
ahhh,, okayy thank you!
The current Sec 3 and Sec 4 students do not learn the chapter on “sum of roots” and “product of roots” as it has been removed from the secondary school A Maths syllabus, so you might wish to explain a little more about it.
:) thank you
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