Kevan's answer to Kc's Secondary 2 Maths Singapore question.
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given xy=6 and y is greater than x,
possible combinations of x and y are (y is 6 and x is 1) or (y is 3 and x is 2)
using these sets of values, sub into x² + y² = 36 would give you (x=1, y=6)
hence , a) is 7² = 49
b) is (-5)² = 25
c) is 1 - 36 = -35
hope this helps :)
possible combinations of x and y are (y is 6 and x is 1) or (y is 3 and x is 2)
using these sets of values, sub into x² + y² = 36 would give you (x=1, y=6)
hence , a) is 7² = 49
b) is (-5)² = 25
c) is 1 - 36 = -35
hope this helps :)
Date Posted:
2 years ago
Part C- answer i got is 35 or 37 though
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