Nathaniel Lukas Christianto's answer to freds <3's Secondary 3 E Maths Singapore question.
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For (b), alternatively, let a = -1/y.
Then ⅕ ≤ a ≤ 1, and we only need to find the greatest value of xa² + a, which is 4, achieved when x = 3 and a = 1.
Then ⅕ ≤ a ≤ 1, and we only need to find the greatest value of xa² + a, which is 4, achieved when x = 3 and a = 1.
Date Posted:
2 years ago
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