Siow Lin Hoe's answer to mich's Secondary 4 A Maths Singapore question.
done
{{ upvoteCount }} Upvotes
clear
{{ downvoteCount * -1 }} Downvotes
Y=(x + 4)/(5-x)
dy/dx = (1-2x)/(5-x)^2
At x-axis, y=0
So, (x+4)/(5-x)=0
So, x+4=0, x=-4
When, x=-4, dy/dx = [1-2(-4)]/[5-(-4)]^2 =9/81=1/9
dy/dx = (1-2x)/(5-x)^2
At x-axis, y=0
So, (x+4)/(5-x)=0
So, x+4=0, x=-4
When, x=-4, dy/dx = [1-2(-4)]/[5-(-4)]^2 =9/81=1/9
Date Posted:
2 years ago
360 Tutoring Program