Damien Liu's answer to Silin's Secondary 3 E Maths Singapore question.
Question 3ab and 4a is correct! I see you understand how to be in single fraction with common denominator!
Maybe what’s confusing or stoping you from answering 4b is knowing that (c+1)2 is equivalent to (c+1)(c+1). Like y2= y(y), 8 square= 8(8).
Maybe what’s confusing or stoping you from answering 4b is knowing that (c+1)2 is equivalent to (c+1)(c+1). Like y2= y(y), 8 square= 8(8).
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