lesterine's answer to kye's Secondary 4 A Maths Singapore question.
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y=a^(b+x)
apply lg on both sides
lg y = lg a^(b+x)
by power law, b+x can be moved down
lg y = (b+x) lg a
lg y = (lg a) x + b lg a
Y = mX + C
apply lg on both sides
lg y = lg a^(b+x)
by power law, b+x can be moved down
lg y = (b+x) lg a
lg y = (lg a) x + b lg a
Y = mX + C
Date Posted:
3 years ago
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