Essentially if you want to solve the modulus to be less than 1, u can just look at the graph. If not, by looking at it logically, when x is less than -2, -2/x will be less than 1 (eg. -2/-2 is 1 then -2/-3 is 2/3 which is less than 1 alr). When x is more than 2, -2/x will be more than -1 (eg -2/2 is -1 then -2/3 will be greater than -1 already) but if we put a modulus to this, it will be come l-2/2l = 1 followed by l-2/3l is 2/3 which is less than 1 which is what the question wants.