Sharon Tham's answer to lara's Secondary 3 A Maths Singapore question.
log y can be negative value, so taking square root of both sides, should write as ...
log y = +or- ( (log 16)/3)
y = 10^((log 16)/3) or 10^(-(log 16)/3)
y = 2.5198421 or 0.396850263
verify that both values satisfy the given equation.
log y = +or- ( (log 16)/3)
y = 10^((log 16)/3) or 10^(-(log 16)/3)
y = 2.5198421 or 0.396850263
verify that both values satisfy the given equation.
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