Jason Jing Ming Quek's answer to Jane's Secondary 4 E Maths Singapore question.
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A) Angle TPQ =90deg ( angles in a semi-circle)
Angle QTP = 35 deg (angles in the same segment)
Angle PQT = 180-35 -90 = 55 deg ( angles in a triangle
Angle QTP = 35 deg (angles in the same segment)
Angle PQT = 180-35 -90 = 55 deg ( angles in a triangle
Date Posted:
3 years ago
Hello, this is the answer for part a) i am still working on part B. Hope it helps you! -jason
Part B) Angle PXQ =180-125 =55 deg (angles on a straight line)
Angle XPQ = 180 - 55 - 55 = 70 deg ( angles in a triangle)
Angle QRS =180-70 =110 (angles in opposite segment are supplementary
Angle XPQ = 180 - 55 - 55 = 70 deg ( angles in a triangle)
Angle QRS =180-70 =110 (angles in opposite segment are supplementary
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