Thank You

This can be done quite easily without long division.

The idea is that since there is a 2x in the numerator, you want to rewrite the -1 such that you can get a multiple of (x - 5)

2x is 2 times of x. So you want a -10 (which is 2 times of -5)


(2x - 1) / (x - 5)

= (2x - 10 + 9) / (x - 5)

= (2x - 10) / (x - 5) + 9/(x - 5)

= 2(x - 5) / (x - 5) + 9/(x - 5)

= 2 + 9/(x - 5)

You can skip the 3rd and 4th line if you want.

huhhhhhh im confused im gna die in sec 3 math

This technique is fairly common and simple.

Recall the distributive law multiplication.

2(x - 5) = 2 × x - 2 × 5 = 2x - 10

You are working backwards in a sense, to factor out the 2x