J's answer to iliketostayathome's Secondary 1 Maths Singapore question.
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Step 1 : There are two possible 130° for ∠BCD so measure 130° on each side and draw the lines.
Step 2 : Use a compass and draw a circle with radius 6cm. Let D be the centre of this circle.
The radius (distance from centre to circumference) is always the same.
There will be two intersection points for the circle, one for each line you've drawn for the 140°
These two points are your D1 and D2.
Step 2 : Use a compass and draw a circle with radius 6cm. Let D be the centre of this circle.
The radius (distance from centre to circumference) is always the same.
There will be two intersection points for the circle, one for each line you've drawn for the 140°
These two points are your D1 and D2.
Date Posted:
3 years ago
Something to note : I can't tell what the actual lengths of AB and AC are on your paper, so the result you get might be different from this.
But the method remains the same. Using the property that a circle's radius remains unchanged. By finding the intersections between the two lines and the circumference, you'll get the right 6cm distance from both D's to A
But the method remains the same. Using the property that a circle's radius remains unchanged. By finding the intersections between the two lines and the circumference, you'll get the right 6cm distance from both D's to A
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