J's answer to Ivey's Secondary 4 A Maths Singapore question.
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sec² x + sec x tan x
1/cos² x + (1/cos x)(sin x / cos x)
= 1/cos² x + sin x / cos² x
= (1 + sin x) / cos² x
= (1 + sin x) / (1 - sin² x)
= (1 + sin x) / [(1 - sin x)(1 + sin x)]
= 1 / (1 - sin x)
(Proved)
1/cos² x + (1/cos x)(sin x / cos x)
= 1/cos² x + sin x / cos² x
= (1 + sin x) / cos² x
= (1 + sin x) / (1 - sin² x)
= (1 + sin x) / [(1 - sin x)(1 + sin x)]
= 1 / (1 - sin x)
(Proved)
Date Posted:
3 years ago
Thank you so much! Sorry for the late comment :((
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