J's answer to Nor Riezqin's Secondary 1 Maths Singapore question.
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No. Not correct.
T1 = 7 = 7 + 0 = 7 + 6(1 - 1)
T2 = 13 = 7 + 6 = 7 + 6(2 - 1)
T3 = 19 = 7 + 12 = 7 + 6(2) = 7 + 6(3 - 1)
T4 = 25 = 7 + 18 = 8 + 6(3) = 7 + 6(4 - 1)
So,
Tn = 7 + 6(n - 1) = 7 + 6n - 6 = 6n + 1
T1 = 7 = 7 + 0 = 7 + 6(1 - 1)
T2 = 13 = 7 + 6 = 7 + 6(2 - 1)
T3 = 19 = 7 + 12 = 7 + 6(2) = 7 + 6(3 - 1)
T4 = 25 = 7 + 18 = 8 + 6(3) = 7 + 6(4 - 1)
So,
Tn = 7 + 6(n - 1) = 7 + 6n - 6 = 6n + 1
Date Posted:
3 years ago
Alternatively,
T1 = 7 = 1 + 6
T2 = 13 = 1 + 12 = 1 + 6(2)
T3 = 19 = 1 + 18 = 1 + 6(3)
T4 = 25 = 1 + 24 = 1 + 6(4)
So,
Tn = 1 + 6n
(or 6n + 1)
T1 = 7 = 1 + 6
T2 = 13 = 1 + 12 = 1 + 6(2)
T3 = 19 = 1 + 18 = 1 + 6(3)
T4 = 25 = 1 + 24 = 1 + 6(4)
So,
Tn = 1 + 6n
(or 6n + 1)
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