EugeneC's answer to dionne's Primary 6 Maths Geometry Singapore question.
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∠JCF = 90 - 28 = 62
∠BCF = 62 - ∠x
∠BCH = 90 - 32 = 58
∠JCH = 58 - ∠x
∠HCF = ∠JCH + ∠x +∠BCF = 90
(58-∠x) + ∠x + (62-∠x) = 90
120 - ∠x = 90
∠x = 30(ans)
∠BCF = 62 - ∠x
∠BCH = 90 - 32 = 58
∠JCH = 58 - ∠x
∠HCF = ∠JCH + ∠x +∠BCF = 90
(58-∠x) + ∠x + (62-∠x) = 90
120 - ∠x = 90
∠x = 30(ans)
Date Posted:
3 years ago
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