J's answer to Alaya's Secondary 1 Maths Singapore question.
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∠GHB = ∠a + ∠d (exterior angle of triangle = sum of two interior opposite angles. The relevant triangle is triangle AHB)
∠HGB = ∠e + ∠c (same property. The relevant triangle is triangle CGE)
∠GHB + ∠HGB + ∠b = 180° (angle sum of triangle GHB)
So ∠a + ∠d + ∠e + ∠c + ∠b = 180°
∠HGB = ∠e + ∠c (same property. The relevant triangle is triangle CGE)
∠GHB + ∠HGB + ∠b = 180° (angle sum of triangle GHB)
So ∠a + ∠d + ∠e + ∠c + ∠b = 180°
Date Posted:
2 years ago
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