Jasper Eng's answer to Alicia's Secondary 4 A Maths Singapore question.
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LHS
= (1 - cos2x) / (1+ cos2x)
= (1 - 2cos^2 (x) + 1) / ( 1 + 2cos^2 (x) - 1)
= (2 - 2cos^2 (x) ) / 2cos^2 (x)
= (1 - cos^2 (x) ) / cos^2 (x)
= sec^2 (x) - 1
= sec^2 (x) - ( sin^2 (x) + cos^2 (x) )
= sec^2 (x) - sin^2 (x) - cos^2 (x)
= RHS (shown)
= (1 - cos2x) / (1+ cos2x)
= (1 - 2cos^2 (x) + 1) / ( 1 + 2cos^2 (x) - 1)
= (2 - 2cos^2 (x) ) / 2cos^2 (x)
= (1 - cos^2 (x) ) / cos^2 (x)
= sec^2 (x) - 1
= sec^2 (x) - ( sin^2 (x) + cos^2 (x) )
= sec^2 (x) - sin^2 (x) - cos^2 (x)
= RHS (shown)
Date Posted:
3 years ago
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