Ai) since the given triangles are similar, the ratios of length are the same:
X/Y = 6/2

The question wanted in terms of y,
So make x the subject:
X/Y = 3
X = 3Y

:.PA = Y + X
= 4Y m //

ii) given similar triangles: (same as part a)
TM / QA = PM / PA
TM / 6 = Y / 4Y
TM = 1/4 * 6
= 1.5cm //

B) redo entire part (a) with h and k instead:
Start by finding PA again: (make x subject)
X/Y = k/h
X = ky/h

PA = y + ky/h

Part (ii):
TM / QA = PM / PA
TM / k = y / (y + ky/h)
TM / k = 1 / (1 + k/h) (remove all y)
TM = k / (1 + k/h)

To simplify more:
TM = kh /(h + k) (multiply all terms by h)
Done