Tutor May Ho, Ex MOE Trained's answer to Choo's Primary 5 Maths Whole Numbers Singapore question.
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As 2 Red are between every 2 green. Start with 2 green. Study the pattern, decide a set or group. Then divide from 130. If 130÷4= 32 1/2, adjust to 32 2/4. Make sure denominator same as divisor 4, so it is 32 remainder 2. Hope you could understand.
Date Posted:
3 years ago
The answer is 86
Each set should be like this :
GRR GRR GRR GRR GRR ..... GRR G
130 ÷ 3 = 43 R 1
(You can do long division and you will see the remainder of 1 at the end.
Alternatively, using the calculator,
130 ÷ 3 = 43⅓ or 43.33333....
There are 43 sets of 3 bulbs (GRR) and a remainder that would make up only ⅓ of a set
⅓ × 3 = 1
Or simply looking at ⅓ would already tell you its 1 bulb out of 3 in a set.
So remainder of 1
This reminder is the last bulb at the end. It's a green bulb.
Number of red bulbs
= 43 sets × 2 red bulbs per set
= 86
GRR GRR GRR GRR GRR ..... GRR G
130 ÷ 3 = 43 R 1
(You can do long division and you will see the remainder of 1 at the end.
Alternatively, using the calculator,
130 ÷ 3 = 43⅓ or 43.33333....
There are 43 sets of 3 bulbs (GRR) and a remainder that would make up only ⅓ of a set
⅓ × 3 = 1
Or simply looking at ⅓ would already tell you its 1 bulb out of 3 in a set.
So remainder of 1
This reminder is the last bulb at the end. It's a green bulb.
Number of red bulbs
= 43 sets × 2 red bulbs per set
= 86
Tutor May might have misinterpreted the question.
In her grouping , there are no red bulbs between the green ones, which does not satisfy the condition that at least 2 red bulbs are in between every 2 green bulbs.
In her grouping , there are no red bulbs between the green ones, which does not satisfy the condition that at least 2 red bulbs are in between every 2 green bulbs.
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