Ryan Patel's answer to ky's Secondary 4 A Maths Singapore question.
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Hope this helps!
Date Posted:
3 years ago
But the discriminant of the gradient is nt lesser or equals to 0
Hi, it is, maybe you have done something wrong in your calculations?
dy/dx = 5x^2/2-4x-15≥-83/5
simplifying gives you (x-0.8)^2 which, if you sketch the graph, touches the x axis and is always above it. Hence, it is ≥0 which agrees with what we want to show: that f’(x)≥0
dy/dx = 5x^2/2-4x-15≥-83/5
simplifying gives you (x-0.8)^2 which, if you sketch the graph, touches the x axis and is always above it. Hence, it is ≥0 which agrees with what we want to show: that f’(x)≥0
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