AC Lim's answer to M's Primary 6 Maths Algebra Singapore question.
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✨Hope this helps
Date Posted:
3 years ago
Can explain why are there two 6/15 in the first model and what is u? Thank you.
Just put it this way.
Ben have 15p
(common multiple of 3 and 5)
Marcus have 15p + u ( we don't know how much more Marcus have than Ben, so is u, unless they received same amount, then no need u))
...
If Ben gave 2/5 to Marcus, meaning gave 6u to Marcus
Marcus have 12p + u more than Ben
(Agreed?, Draw model if you cannot imagine).
12p + u = 64
If Ben gave 2/3 to Marcus, meaning gave 10p to Marcus.
Marcus will have 20p + u.... Can see?
20p + u = 144
The difference
20p + u - 12p - u = 144 - 64
8p = 80
p = 10
Ben at 1st = 15p = 15×10 = 150
Ben have 15p
(common multiple of 3 and 5)
Marcus have 15p + u ( we don't know how much more Marcus have than Ben, so is u, unless they received same amount, then no need u))
...
If Ben gave 2/5 to Marcus, meaning gave 6u to Marcus
Marcus have 12p + u more than Ben
(Agreed?, Draw model if you cannot imagine).
12p + u = 64
If Ben gave 2/3 to Marcus, meaning gave 10p to Marcus.
Marcus will have 20p + u.... Can see?
20p + u = 144
The difference
20p + u - 12p - u = 144 - 64
8p = 80
p = 10
Ben at 1st = 15p = 15×10 = 150
That all for explanation. : ) Hope you can understand.
But still don't understand why when ben gives 6p to Marcus, Marcus will have 12p + u instead of 6p + u?
Oh...
You have 4
I have 4
You give 1 to me,you left 3
I have 4 +1 = 5, I have 1+1 more than you....
You have 4
I have 4
You give 1 to me,you left 3
I have 4 +1 = 5, I have 1+1 more than you....
We find the difference ...
Find how much Marcus has MORE THAN Ben.
Find how much Marcus has MORE THAN Ben.
I am crystal clear now. Thanks a million.