Ginnie Lai's answer to dogman's Primary 6 Maths Singapore question.
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Since BA is parallel to CF,
angle BAC = angle ACF = 48
angle CEF = 180 - 105 = 75 (angles on a straight line)
angle CFE = 180 - 48 - 75 = 57 (angles in a triangle)
angle BAC = angle ACF = 48
angle CEF = 180 - 105 = 75 (angles on a straight line)
angle CFE = 180 - 48 - 75 = 57 (angles in a triangle)
Date Posted:
3 years ago
ooohhhh, I understand now, thanks!!
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