EugeneC's answer to Clara's Secondary 3 E Maths Singapore question.
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1a) (x/3) + (y/2) =1
(2x+3y)/6 = 1
3y = -2x + 6
y = -(2/3)x + 2
Gradient = -2/3
1b) when y = 0,
-2 = -(2/3)x
2 = (2/3)x
x = 3
(3,0) [answer]
(2x+3y)/6 = 1
3y = -2x + 6
y = -(2/3)x + 2
Gradient = -2/3
1b) when y = 0,
-2 = -(2/3)x
2 = (2/3)x
x = 3
(3,0) [answer]
Date Posted:
3 years ago
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