AC Lim's answer to Cshjwrk's Primary 6 Maths Measurement Singapore question.
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Common multiple of 90 and 120 = 360
Machine A, 90 mins→360u
Therefore 1min = 360u÷90 = 4u
Machine B , 120 mins→ 360u
Therefore, 1min = 360÷120 = 3u
Given, 1 min faster machine print 6 more pages.
So, 4u-3u=6,
1u = 6
Total for each machine = 360u = 360×6 = 2160 pages
Total for both machines = 2160×2 = 4320 pages.
Machine A, 90 mins→360u
Therefore 1min = 360u÷90 = 4u
Machine B , 120 mins→ 360u
Therefore, 1min = 360÷120 = 3u
Given, 1 min faster machine print 6 more pages.
So, 4u-3u=6,
1u = 6
Total for each machine = 360u = 360×6 = 2160 pages
Total for both machines = 2160×2 = 4320 pages.
Date Posted:
3 years ago
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