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primary 5 | Maths
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Pls help
Date Posted: 3 years ago
Views: 202
From 11 to 99, there are (99 - 11 + 1) = 89 numbers in them.
This takes up a total of 89 x 2 = 178 digits.
After this, number of digits remaining
= 337 - 178
= 159
The remaining participants has 3 digits in their tags each, so the number of participants having 3 digits in their tags
= 159 / 3
= 53
So, the total number of participants
= 89 + 53
= 142
This takes up a total of 89 x 2 = 178 digits.
After this, number of digits remaining
= 337 - 178
= 159
The remaining participants has 3 digits in their tags each, so the number of participants having 3 digits in their tags
= 159 / 3
= 53
So, the total number of participants
= 89 + 53
= 142
See 1 Answer
By calculating al numbers from 11 to 337 you have to :
337-11= 326 this is the amount from 12 - 337 and since 11 is used it will be :
326+1= 327
337-11= 326 this is the amount from 12 - 337 and since 11 is used it will be :
326+1= 327
I meant to say ‘all’ not ‘al’
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