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primary 6 | Maths
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Date Posted: 3 years ago
Views: 254
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Make the unit area of C (20units) small such that it will be divisible in the later steps.
Find the shaded area of C which will be 5
Using the denominator of shaded area of A and B, the total area of A and B is 12
Using the numerator of shaded area of A and B, the total shaded area of A and B is 5 which is equal to the shaded area of C
Use simultaneous equation to find what is 1 unit of A (i don't know if simple simultaneous equation solving is in your P6 syallabus)
From there just substitute 2 into equation 3 to get 1 unit of B.
Afterwards the final step, just multiply to each area as according to the unit (denominator) A and B have to find the ratio.
Remember to put at simplest ratio form for final answer.
Hope this helps!
Find the shaded area of C which will be 5
Using the denominator of shaded area of A and B, the total area of A and B is 12
Using the numerator of shaded area of A and B, the total shaded area of A and B is 5 which is equal to the shaded area of C
Use simultaneous equation to find what is 1 unit of A (i don't know if simple simultaneous equation solving is in your P6 syallabus)
From there just substitute 2 into equation 3 to get 1 unit of B.
Afterwards the final step, just multiply to each area as according to the unit (denominator) A and B have to find the ratio.
Remember to put at simplest ratio form for final answer.
Hope this helps!
Date Posted:
3 years ago
But the answer is 1:1
Really? Oh crap my bad. The final step is Area A : Area B = 2units x 3 : 3units x 2 = 6 : 6 = 1 : 1
Sorry. It was late at night. I mixed up my denominator
Sorry. It was late at night. I mixed up my denominator
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