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secondary 4 | A Maths
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hello can someone help me with this question? i’m a bit confused on how to approach it
Date Posted: 3 years ago
Views: 275
You should first express f(x) as x + 4/x (dividing the numerator by the denominator) and not use quotient rule like the other tutor did.
f(x) = x + 4/x
f(x) = x + 4 * x^-1
Differentiating,
f'(x) = 1 + 4 (-1) * x^-2
f'(x) = 1 - (4 / x^2)
At x = 4,
f'(x) = 1 - (4 / 4^2)
f'(x) = 1 - 1/4
f'(x) = 3/4
So, the gradient of the tangent at the point where x = 4 is 3/4.
f(x) = x + 4/x
f(x) = x + 4 * x^-1
Differentiating,
f'(x) = 1 + 4 (-1) * x^-2
f'(x) = 1 - (4 / x^2)
At x = 4,
f'(x) = 1 - (4 / 4^2)
f'(x) = 1 - 1/4
f'(x) = 3/4
So, the gradient of the tangent at the point where x = 4 is 3/4.
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done
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If f(x) is your function, then f'(x) is your derivative (which also means gradient function).
You can then sub in an x-value to find the value of the gradient at the given x-value.
You can then sub in an x-value to find the value of the gradient at the given x-value.
Date Posted:
3 years ago
thank you so much! have a nice day :)
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