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secondary 3 | A Maths
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Hi, can someone help me with question 5c, why is it not a polynomial? Thanks in advance!
Date Posted: 3 years ago
Views: 188
https://www.mathsisfun.com/algebra/polynomials.html
You have to be clear on what defines a polynomial first.
The answer for 5c) is :
(6x⁴ - 3x³ - 28x² - x - 10) / (3 - 2x)
= -3x³ - 3x² + 19/2 x + 59/4 - 217/(4(3 - 2x))
There is a remainder of -217/4 and thus as we can see, the expression has a reciprocal of 3 - 2x in the last term (its in the denominator.)
For that term, we are dividing by a variable so the whole expression cannot be considered a polynomial.
You have to be clear on what defines a polynomial first.
The answer for 5c) is :
(6x⁴ - 3x³ - 28x² - x - 10) / (3 - 2x)
= -3x³ - 3x² + 19/2 x + 59/4 - 217/(4(3 - 2x))
There is a remainder of -217/4 and thus as we can see, the expression has a reciprocal of 3 - 2x in the last term (its in the denominator.)
For that term, we are dividing by a variable so the whole expression cannot be considered a polynomial.
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Hope this helps!
Date Posted:
3 years ago
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