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secondary 3 | E Maths
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In positive index notation
Date Posted: 3 years ago
Views: 167
Expand everything out first.
So, (m^-7n^-1/2)^2 × (m^3n^-3)^-1/3
= m^-14n^-1 × m^-1n
= m^-15
= 1/m^15
So, (m^-7n^-1/2)^2 × (m^3n^-3)^-1/3
= m^-14n^-1 × m^-1n
= m^-15
= 1/m^15
Yea, careless mistake on my end. My bad
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done
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Hi pl see above.
Date Posted:
3 years ago
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