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secondary 3 | E Maths
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I did the equation until I am stuck at this place where I got -3x+x+10 and I don’t know how to continue
Date Posted: 3 years ago
Views: 149
Solve it like any other quadratic eqn
-3x^2 + x + 10 = 0
(x-2)(3x+5) = 0
x = 2, x = -5/3
-3x^2 + x + 10 = 0
(x-2)(3x+5) = 0
x = 2, x = -5/3
See 1 Answer
(7 - 3x)(x + 2) = 4
7x + 2(7) - 3x(x) - 3x(2) = 4
7x + 14 - 3x² - 6x = 4
14 + x - 3x² = 4
10 + x - 3x² = 0
(3x + 5)(2 - x) = 0
3x + 5 = 0 or 2 - x = 0
3x = -5 or x = 2
x = -5/3 (or-1⅔)
∴ x = -5/3 or x = 2
7x + 2(7) - 3x(x) - 3x(2) = 4
7x + 14 - 3x² - 6x = 4
14 + x - 3x² = 4
10 + x - 3x² = 0
(3x + 5)(2 - x) = 0
3x + 5 = 0 or 2 - x = 0
3x = -5 or x = 2
x = -5/3 (or-1⅔)
∴ x = -5/3 or x = 2
Alternatively, bring the terms to the other side (or multiply both sides of equation by -1)
10 + x - 3x² = 0
3x² - x - 10 = 0
(3x + 5)(x - 2) = 0
3x + 5 = 0 or x - 2 = 0
3x = -5 or x = 2
x = -5/3
(Or -1⅔)
10 + x - 3x² = 0
3x² - x - 10 = 0
(3x + 5)(x - 2) = 0
3x + 5 = 0 or x - 2 = 0
3x = -5 or x = 2
x = -5/3
(Or -1⅔)
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