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Question
secondary 3 | A Maths
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Date Posted: 3 years ago
Views: 279
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From eq 2- eq3
Y=4-2×
Sub eq3 into eq1
(4-2x)^2 -4x =0
Expand (4-2x)^2 into (4-2x)(4-2x) = 16+2(4)(-2x)+4×^2 then subtract 4x
Ull get quadratic equation, u cn solve for x
Then once u find x
Sub into eq3 to find y
Y=4-2×
Sub eq3 into eq1
(4-2x)^2 -4x =0
Expand (4-2x)^2 into (4-2x)(4-2x) = 16+2(4)(-2x)+4×^2 then subtract 4x
Ull get quadratic equation, u cn solve for x
Then once u find x
Sub into eq3 to find y
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