Ask Singapore Homework?
Upload a photo of a Singapore homework and someone will email you the solution for free.
Question
secondary 3 | A Maths
One Answer Below
Anyone can contribute an answer, even non-tutors.
Asap
Date Posted: 3 years ago
Views: 302
See 1 Answer
It won't be sufficient to just state that (3k + 5)² - 4(1)(-3) > 0 . Further working needs to be shown to justify it.
Discriminant
= (3k + 5)² - 4(1)(-3)
= (3k + 5)² + 12
Now,
(3k + 5)² ≥ 0 for all real k
(The square of any real value is either 0 or positive)
So (3k + 5)² + 12 ≥ 12
→ (3k + 5)² + 12 > 0
Since the discriminant > 0 for all real k , the roots of the equation are always real (and distinct).
Discriminant
= (3k + 5)² - 4(1)(-3)
= (3k + 5)² + 12
Now,
(3k + 5)² ≥ 0 for all real k
(The square of any real value is either 0 or positive)
So (3k + 5)² + 12 ≥ 12
→ (3k + 5)² + 12 > 0
Since the discriminant > 0 for all real k , the roots of the equation are always real (and distinct).
Ah yes i agree you have to show the full step thats my bad
360 Tutoring Program