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secondary 4 | E Maths
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pls help. need it urgently
Date Posted: 3 years ago
Views: 299
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What you're probably looking for is this :
9a² - 12a - b² + 4
= 9a² - 12a + 4 - b²
= (3a)² - 2(3a)(2) + 2² - b²
= (3a - 2)² - b²
= (3a - 2 + b)(3a - 2 - b)
The 3rd step uses the property (x - y)² = x² - 2xy + y² , whereby your x = 3a and y= 2.
The last step uses the property x² - y² = (x + y)(x - y) , whereby your x = 3a - 2 and y = b
9a² - 12a - b² + 4
= 9a² - 12a + 4 - b²
= (3a)² - 2(3a)(2) + 2² - b²
= (3a - 2)² - b²
= (3a - 2 + b)(3a - 2 - b)
The 3rd step uses the property (x - y)² = x² - 2xy + y² , whereby your x = 3a and y= 2.
The last step uses the property x² - y² = (x + y)(x - y) , whereby your x = 3a - 2 and y = b
It’s one of the rare occasions we do a 3-1 grouping of terms rather than the usual 2-2 grouping of terms.
Slightly more difficult. But compared to the ones that the user Olivia Tan usually posts, this is very easy actually.
Recognition of properties as usual.
Recognition of properties as usual.
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