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secondary 2 | Maths
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Date Posted: 3 years ago
Views: 526
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Sum of exterior angles of a polygon = 360°
So, 2x° + 4x° + 5x° + 9x° + 10x° = 360°
30x° = 360°
x = 360°/ 30° = 12
Smallest exterior angle = 2x° = (2×12)° = 24°
Next,
The sum of an interior angle and its corresponding exterior angle is always 180°
So the smaller the interior angle, the larger the exterior angle must be in order to add up to 180°
So if we want the smallest interior angle, we subtract the biggest exterior angle from 180°
Biggest exterior angle = 10x° = (10×12)° = 120°
Smallest interior angle = 180° - 120° = 60°
So, 2x° + 4x° + 5x° + 9x° + 10x° = 360°
30x° = 360°
x = 360°/ 30° = 12
Smallest exterior angle = 2x° = (2×12)° = 24°
Next,
The sum of an interior angle and its corresponding exterior angle is always 180°
So the smaller the interior angle, the larger the exterior angle must be in order to add up to 180°
So if we want the smallest interior angle, we subtract the biggest exterior angle from 180°
Biggest exterior angle = 10x° = (10×12)° = 120°
Smallest interior angle = 180° - 120° = 60°
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