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secondary 3 | E Maths
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Please help. Thank you!
Date Posted: 3 years ago
Views: 235
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Tangent at circle = 90. Hope this helps
Date Posted:
3 years ago
Hi, can explain further. I don’t really understand. I understand the tangent at a circle but how fo u get the specific angles?
OA = OE = radii
Therefore, angle OEA = OAE = 30° (Isosceles triangle)
Angle AEQ = 90 - 30 = 60°
Angle AED = 90° (You'd marked)
So, Angle OED = 60°
Hence, angle DEP = 180 - 60 - 30 - 60 =30°
Or
Angle DEP = 180 -AEQ-AED
= 180-60-90
=30°
Therefore, angle OEA = OAE = 30° (Isosceles triangle)
Angle AEQ = 90 - 30 = 60°
Angle AED = 90° (You'd marked)
So, Angle OED = 60°
Hence, angle DEP = 180 - 60 - 30 - 60 =30°
Or
Angle DEP = 180 -AEQ-AED
= 180-60-90
=30°
Okay I finally understand.Thank you so much!!
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