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secondary 3 | E Maths
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Date Posted: 3 years ago
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a)
Spinner B has six numbers, and two of them are '5' .
Probability that the needle stops on '5' = 2 out of 6 = 2/6 = 1/3
b)
Spinner A has five numbers, and only one of them is a '3' .
Probability that the Spinner A needle stops on '3' = 1 out of 5 = 1/5
For Spinner B, there is only one '3' .
Probability the needle for Spinner B stops on '3' = 1 out of 6 = 1/6
Since 1/5 is greater than 1/6, the probability of the needle in Spinner A stopping on '3' is greater than that of the needle in Spinner B stopping on '3'.
So, Spinner A is more likely to stop on '3'.
Spinner B has six numbers, and two of them are '5' .
Probability that the needle stops on '5' = 2 out of 6 = 2/6 = 1/3
b)
Spinner A has five numbers, and only one of them is a '3' .
Probability that the Spinner A needle stops on '3' = 1 out of 5 = 1/5
For Spinner B, there is only one '3' .
Probability the needle for Spinner B stops on '3' = 1 out of 6 = 1/6
Since 1/5 is greater than 1/6, the probability of the needle in Spinner A stopping on '3' is greater than that of the needle in Spinner B stopping on '3'.
So, Spinner A is more likely to stop on '3'.
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