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Hope this helps eh, thanks.
Date Posted:
3 years ago
thx :)
sec(-2A)
= 1/cos(-2A)
= 1/cos(2A) (recall that cos(-θ) = cos(θ) )
= 1/(2cos²A - 1) (see formula sheet)
= 1/(2(-3/5)² - 1)
= 1/(2(9/25) - 1)
= 1/(18/25 - 1)
= 1/(-7/25)
= -25/7 or -3 4/7
= 1/cos(-2A)
= 1/cos(2A) (recall that cos(-θ) = cos(θ) )
= 1/(2cos²A - 1) (see formula sheet)
= 1/(2(-3/5)² - 1)
= 1/(2(9/25) - 1)
= 1/(18/25 - 1)
= 1/(-7/25)
= -25/7 or -3 4/7
thx :)