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secondary 3 | A Maths
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secondary 3 chevron_right A Maths chevron_right Singapore

Anyone knows how to do? Thankyouu

Date Posted: 3 years ago
Views: 147

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y = 3px² - 12x + p, p is negative
On the x-axis , y = 0.
So when the x-axis touches the curve, 3px² - 12x + p = 0 (I am interpreting this as touching the curve at exactly one point, i.e the x-axis is the tangent to the curve)
For one point of intersection only, we want real and repeated roots. So discriminant ('b² - 4ac') = 0
(-12)² - 4(3p)(p) = 0
144 - 12p² = 0
12p² = 144
p² = 12
p = √12 (rejected as p is negative) or p = -√12
p = -√(4×3) = -√4 √3= -2√3
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3 years ago
Thank you!!