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secondary 3 | E Maths
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In the ans sheet the answer is X=0..However I got 2 answers, X=0 and X=1. Why did I get 2 answers? Is X=1 supposed to be rejected? Is the method I used a fluke? Original question is in the top right hand corner.(Original question says to leave the answer in 3sf)
Date Posted: 3 years ago
Views: 177
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Your method is correct. But what you should have done is to reject the solution x = 1.
x cannot be equal to 1 as that would mean x - 1 = 0.
Look back at your original equation. It would result in the denominators being 0, and division by 0 is undefined.
So we have to reject x = 1 as a possible solution, which means the only solution is x = 0
x cannot be equal to 1 as that would mean x - 1 = 0.
Look back at your original equation. It would result in the denominators being 0, and division by 0 is undefined.
So we have to reject x = 1 as a possible solution, which means the only solution is x = 0
Oh thanks
Btw your original equation's denominator seems to be different from your factorisation on the left.
The one on the left is x² + 2x - 3 but the original equation's is x² - x + 3.
Is there some typo?
The one on the left is x² + 2x - 3 but the original equation's is x² - x + 3.
Is there some typo?
Yea the question I wrote on the right has a typo, it's supposed to be x²+2x-3, sorry
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