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secondary 2 | Maths
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Divya
Divya

secondary 2 chevron_right Maths chevron_right Singapore

This is a basic maths question

Date Posted: 3 years ago
Views: 189
Divya
Divya
3 years ago
I need help with this using differentiation rule

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Zhe Xun
Zhe Xun's answer
113 answers (Tutor Details)
1st
Hope this helps, but maybe the actual answer could be an explanation of how v is proportionate to t

E.g because cuberoot t is a smaller power than t
Divya
Divya
3 years ago
I am sorry but i cant get negative seven over 242 i keep getting different answers
Zhe Xun
Zhe Xun
3 years ago
Would like to see your working
Divya
Divya
3 years ago
I did 6(1/3)(8)^-2/3(4(8))+1^-1+6(8)^1/3(-1)(4(8))+1^-2(4)

Which gives me error on my calculator
Zhe Xun
Zhe Xun
3 years ago
I think the brackets are wrong

Should be (4*8+1)^-1 instead of (4(8))+1^-1
Same for the ^2
Divya
Divya
3 years ago
Okay sure let me check it up
J
J
3 years ago
v = 6t¹/³ (4t + 1)-¹

dv/dt = ⅓(6t-²/³) (4t + 1)-¹ + 6t¹/³ (-1)(4)(4t + 1)-²
= 2 / (t²/³(4t + 1)) - 24t¹/³ / (4t + 1)²
= 2 / (³√t² (4t + 1)) - 24³√t / (4t + 1)²

When t = 8,

dv/dt = 2 / (³√8² (4(8)+ 1)) - 24³√8 / (4(8)+ 1)²

= 2 / (³√64 (33)) - 24(2) / 33²

= 2 / (4 (33)) - 48 / 1089

= 11/726 - 32 / 726

= -21/726

= -7/242
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Zhe Xun
Zhe Xun's answer
113 answers (Tutor Details)
Another working to simplify the first solution
Divya
Divya
3 years ago
Thank you so much it worked !!