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secondary 2 | Maths
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hi i need help
Date Posted: 3 years ago
Views: 461
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Draw a diagonal of the square to divide into 2 identical right angled triangles.
Each triangle has a base equal to diameter of the circle, d (or 2r) , and a height equal to its radius , r
Area of square = area of 2 triangles
= 2 x ½ x 2r x r
= 2r²
Area of circle = πr²
Remaining area not occupied by the square = πr² - 2r² = (π-2)r²
The shaded part is equal to the other 3 parts that are not occupied by the square.
Area of shaded part = ¼ of remaining area = ¼(π-2)r²
Probability required = area of shaded part / area of circle
= ¼(π-2)r² / πr²
= ¼(π-2) / π
= ¼ - 1/(2π)
Each triangle has a base equal to diameter of the circle, d (or 2r) , and a height equal to its radius , r
Area of square = area of 2 triangles
= 2 x ½ x 2r x r
= 2r²
Area of circle = πr²
Remaining area not occupied by the square = πr² - 2r² = (π-2)r²
The shaded part is equal to the other 3 parts that are not occupied by the square.
Area of shaded part = ¼ of remaining area = ¼(π-2)r²
Probability required = area of shaded part / area of circle
= ¼(π-2)r² / πr²
= ¼(π-2) / π
= ¼ - 1/(2π)
Sorry, I should add that you have to use π = 22/7 for the last step.
So it should be ¼ - 1/(2x22/7)
= ¼ - 1/(44/7)
= ¼ - 7/44
= 11/44 - 7/44
= 4/44
= 1/11
So it should be ¼ - 1/(2x22/7)
= ¼ - 1/(44/7)
= ¼ - 7/44
= 11/44 - 7/44
= 4/44
= 1/11
done
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Date Posted:
3 years ago
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