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secondary 2 | Maths
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can anyone explain how u arrive at the answer?
Date Posted: 3 years ago
Views: 405
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a)
R is directly proportional to l
Let R = hl, h is a constant ①
R is inversely proportional to r²
Let R = g/r², g is a constant ②
① × ② :
R × R = hl × g/r²
R² = ghl / r²
R = √(ghl / r²)
R = √(ghl) / √(r²)
R = √(gh) √l / r
R = k√l / r, where k = √(gh)
b)
rR = k√l
r = k√l / R
R is directly proportional to l
Let R = hl, h is a constant ①
R is inversely proportional to r²
Let R = g/r², g is a constant ②
① × ② :
R × R = hl × g/r²
R² = ghl / r²
R = √(ghl / r²)
R = √(ghl) / √(r²)
R = √(gh) √l / r
R = k√l / r, where k = √(gh)
b)
rR = k√l
r = k√l / R
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