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secondary 3 | A Maths
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Date Posted: 3 years ago
Views: 174
log5 (2.45)
= log5 (2 9/20)
= log5 (49/20)
= log5 (49) - log5 (20)
= log5 (7)² - log5 (5 x 4)
= 2 log5 (7) - log5 (5) - log5 (4)
= 2p - 1 - log5 (2)²
= 2p - 1 - 2 log5 (2)
= 2p - 1 - 2m
= log5 (2 9/20)
= log5 (49/20)
= log5 (49) - log5 (20)
= log5 (7)² - log5 (5 x 4)
= 2 log5 (7) - log5 (5) - log5 (4)
= 2p - 1 - log5 (2)²
= 2p - 1 - 2 log5 (2)
= 2p - 1 - 2m
See 1 Answer
log5 (2.45)
= log5 (2 9/20)
= log5 (49/20)
= log5 (49) - log5 (20)
= log5 (7)² - log5 (5 x 4)
= 2 log5 (7) - log5 (5) - log5 (4)
= 2p - 1 - log5 (2)²
= 2p - 1 - 2 log5 (2)
= 2p - 1 - 2m
= log5 (2 9/20)
= log5 (49/20)
= log5 (49) - log5 (20)
= log5 (7)² - log5 (5 x 4)
= 2 log5 (7) - log5 (5) - log5 (4)
= 2p - 1 - log5 (2)²
= 2p - 1 - 2 log5 (2)
= 2p - 1 - 2m
Hi, can u pls check out my question that I just posted? It is a differentiation sec 4 Amaths question. I rlly need help
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